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How do you count the valence electrons of an atom?

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The number of valence electrons is just how many electrons an atom has in its outer shell. It's easy to figure out if you've got a periodic table. (See the link to the left of this answer for a good periodic table).

All the elements in each column have the same number of electrons in their outer shells. All the elements in the first column all have a single valence electron (H, Li, Na, K, etc.).

The second column elements all have 2 valence electrons (Be, Mg, Ca, Sr, etc.).

Skipping over the gap, go to the Group 3 elements, which all have 3 valence electrons (B, Al, Ga, etc.).

The elements in the next column (C, Si, Ge, etc.) all have 4 valence electrons.

The elements in the next column (N, P, As, etc.) all have, yes, you guessed it, 5 valence electrons.

O, S, Se, and the others in this column have 6 valence electrons.

The halogens in the next-to-last column (F, Cl, Br, etc.) have 7 valence electrons.

The noble gases in the right-most column (Ne, Ar, Kr, etc.) all have 8 electrons in their out except for He, which only has 2 electrons.

If an atom is an ion, you must include the charge also:

For a positive ion, for each charge subtract one electron, *for instance, Na+ has 1-1 = 0, BUT it has 8 valence electrons because it has the same electron configuration as Ne. Just as K+ has the same configuration as Ar. Therefore, the Alkali metals will have 8 valence electrons.

For a negative ion, add one electron for each charge, for instance, O2- has 6+2 = 8 valence electrons

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First answer by JEK. Last edit by Ellielou24. Contributor trust: 4 [recommend contributor]. Question popularity: 64 [recommend question]

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